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Is there any function to plot vectors in form $(x,y,z)$ where first coordinate is X value, second- Y value and color of square represents third coordinate? It should look like ArrayPlot.

Here is a sample of my data (http://pastebin.com/nHprReDu) and the results I obtain using ListDensityPlot:

enter image description here

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ListDensityPlot will deal with data in that format. An interpolation order of zero will reproduce the "blocky" ArrayPlot output as well.

data = Flatten[Table[{x, y, Sin[x] + Sin[y]}, {x, -3 Pi, 3 Pi}, {y, -3 Pi, 3 Pi}], 1];
ListDensityPlot[data, InterpolationOrder -> 0]

Mathematica graphics

Thank you for posting your data. Unfortunately, the data you have is not regularly sampled, hence the irregular shapes in the ListDensityPlot. However, you can interpolate and resample if you want "square" blocks. Below, data is your data from pastebin.

if = Interpolation[data];
ListDensityPlot[
 Flatten[Table[{x, y, if[x, y]}, {x, 1, 23, 2}, {y, 1, 14}], 1],
 InterpolationOrder -> 0
]

Mathematica graphics

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  • $\begingroup$ Thank you for idea, but in my case it returns not only squares, what's weird because values are different $\endgroup$
    – pupilx
    Commented Jan 26, 2017 at 22:16
  • $\begingroup$ @pupilx You should add your data and the results in the question, so we can compare results. $\endgroup$
    – MarcoB
    Commented Jan 26, 2017 at 22:18
  • $\begingroup$ Please see my edit $\endgroup$
    – pupilx
    Commented Jan 26, 2017 at 22:31
  • $\begingroup$ @pupilx Thank you for the data. I have amended my answer. Take a look at the new version. $\endgroup$
    – MarcoB
    Commented Jan 26, 2017 at 22:41
  • $\begingroup$ Thank you, it helps me a lot. The most important for me is not to lose information if value < 1, because then I need to construct true/false matrix , will it be ok? $\endgroup$
    – pupilx
    Commented Jan 26, 2017 at 22:47

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