How can I breakdown different segment of the graph

Question

I have constructed a graph using ListLinePlot, using the existing input data from the matrix calculation.

May I ask how can I create a different segment based on existing graph. The graph x-axis ranges from 0 to 540. I need to create three segments, based on the existing graph that I have.

So between 0 to 540, I need help in creating three segments from the existing data to 0-220, 221-421, 422 to 540. I have tried using DataRange, but the outcomes are still the same.

Appreciate your help. Thanks

Answer 1

lst1 = Accumulate[RandomReal[{-1, 1}, 540]];

1. Restructure your input data:

lst2 = MapIndexed[{#2[[1]], #} &, lst1];

{data1, data2, data3} = {lst2[[;; 220]], lst2[[221 ;; 421]], lst2[[422 ;;]]};

ListLinePlot[{data1, data2, data3} ]

2. Use Mesh and MeshShading:

ListLinePlot[lst1, Mesh -> {{221, 422}}, MeshShading -> {Red, Blue, Green}]

3. Use ColorFunction that specifies different colors for different values of x:

ListLinePlot[lst1, ColorFunctionScaling -> False, 
 ColorFunction->Function[{x, y}, Which[x <= 220, Orange, 221 <= x < 421, Cyan, True, Red]]]

4. Plot each piece separately with appropriate DataRange values and combine with Show:

ranges = {{1, 220}, {221, 421}, {422, 540}};
colors = {Red,  Green, Purple};

plots = ListLinePlot[lst1[[Span @@ #]],  DataRange -> #, 
     PlotStyle -> #2] & @@@ Transpose[{ranges, colors}];
Show[plots, PlotRange -> All]

5. Post-process ListLinePlot output to add different directives for different pieces:

ListLinePlot[lst1] /. 
 Line[x_] :> ({#, Line[x[[Span @@ #2]]]} & @@@ Transpose[{colors, ranges}])