Skip to main content

All Questions

Filter by
Sorted by
Tagged with
5 votes
1 answer
271 views

Quantum Field Regularization: Choice between ExpIntegralE and Gamma for Casimir Effect

For the Casimir effect with exponential regularization, we compute the vacuum energy between the plates (somewhat simplified) with: $$\omega = c\ \sqrt{q^2+k_z^2}$$ $$ E = \sum_{k_z=n\pi/a} 2 \int\...
Jos Bergervoet's user avatar
1 vote
1 answer
242 views

Discrepancy with Hurwitz Zeta function

I've come across an issue while using Wolfram Mathematica that I don't quite understand. Consider the following symbolic computation: ...
stefan_chem's user avatar
0 votes
1 answer
85 views

Finite result under "Integrate" while infinite under "NIntegrate" of a complicated integral with "NSum"

I have been trying to compute the following complicated integral along with summation, details codes/function of which is given below: ...
R. Bhattacharya's user avatar
4 votes
1 answer
196 views

How to calculate the sum of the series of Hermite polynomial?

I want to calculate the infinite sum of Hermite polynomials, which works fine with older versions of Mathematica, but with version 13 it doesn't. The infinite sum is: ...
Klaus's user avatar
  • 43
0 votes
0 answers
53 views

Evaluation of a double summation invovlving hypergeometric and exponential functions

I am trying to compute the following double summation over the indices, $m$ and $n$, which involves the hypergeometric function, ${}_2 F_1$, an exponential function and, factorials as a part of a ...
JayanthJ's user avatar
1 vote
1 answer
158 views

How does Mathematica evaluate these sum and integral?

How does Mathematica internally evaluate the following (interrelated) sum and integral, and how does it do the subsequent simplification? (I mean, based on what mathematical facts?) ...
Iosif Pinelis's user avatar
4 votes
5 answers
350 views

Calculating the Dottie number using an infinite series

The Dottie number is the solution to the equation $\cos(x) = x$ It is approximately equal to $0.739085133215160641655312.$ This number can be expressed analytically in the following form (see this ...
George Pa1's user avatar
0 votes
2 answers
491 views

Sum a certain hypergeometric-function-based expression pertaining to an integration problem

I would like to sum over the index $h$ from 3 to $\infty$, the expression ...
Paul B. Slater's user avatar
8 votes
2 answers
392 views

Calculating sum of BesselJ[n, x]

My friend has a sum in his research paper that looks like this $$ \sum_{n=-\infty}^{\infty}\frac{J_n^2(x)}{n-\kappa}. $$ He was able to calculate this sum analytically, by substituting the ...
hayk's user avatar
  • 215
9 votes
2 answers
292 views

Infinite sum not evaluated unless split into even and odd terms

This sum s = Sum[Gamma[k/2]/(2 k!), {k, 1, ∞}] $\sum _{k=1}^{\infty } \frac{\Gamma \left(\frac{k}{2}\right)}{2 k!}$ is returned unevaluated (version 10.1.0). ...
Dr. Wolfgang Hintze's user avatar
13 votes
2 answers
661 views

Asymptotics of $\frac{\sum _{i=0}^{\lfloor n/2 \rfloor} {2(n-2i) \choose n-2i} {n \choose 2i} {4i \choose 2i}}{2^{3n - 1}}$

I am fairly sure that asymptotically $$\frac{\sum _{i=0}^{\lfloor n/2 \rfloor} {2(n-2i) \choose n-2i} {n \choose 2i} {4i \choose 2i}}{2^{3n - 1}} \sim \frac{2}{\pi n}.$$ I tried Limit[n*Sum[...
Simd's user avatar
  • 1,119
13 votes
3 answers
544 views

Find asymptotics of $\sum\limits_{i=0}^{n/3} 2^i \binom{n-i-1}{\frac{2n}{3}-1}$

I have an expression 2^n / Sum[ 2^i Binomial[ n - i - 1, 2n/3 - 1], { i, 0, n/3}] ...
Simd's user avatar
  • 1,119