The easiest way to get the Jacobian is
D[a,{b}]
To get the format of a matrix, you would do MatrixForm[D[f, {x}]
, or D[f, {x}]//MatrixForm
, as the comment by azdahak says.
There is no special matrix type in MMA - it's internally always stored as a list of lists.
Edit
Since this question is partly about the format of the matrix and its elements, I thought it's worth adding a definition that makes calculus output look prettier, and in the case of the Jacobian lets you write symbolic matrices like this:
$\left(
\begin{array}{cc}
\frac{\partial f_{\text{x}}}{\partial x} &
\frac{\partial f_{\text{x}}}{\partial y} \\
\frac{\partial f_{\text{y}}}{\partial x} &
\frac{\partial f_{\text{y}}}{\partial y} \\
\end{array}
\right)$
The definition was initially posted as a comment on the Wolfram Blog:
Derivative /:
MakeBoxes[Derivative[α__][f1_][vars__Symbol],
TraditionalForm] :=
Module[{bb, dd, sp},
MakeBoxes[dd, _] ^=
If[Length[{α}] == 1, "\[DifferentialD]", "\[PartialD]"];
MakeBoxes[sp, _] ^= "\[ThinSpace]";
bb /: MakeBoxes[bb[x__], _] := RowBox[Map[ToBoxes[#] &, {x}]];
FractionBox[ToBoxes[bb[dd^Plus[α], f1]],
ToBoxes[Apply[bb,
Riffle[Map[bb[dd, #] &,
Select[({vars}^{α}), (# =!= 1 &)]], sp]
]
]
]
]
With this, you can get the above matrix form with traditional partial derivatives like this:
First define the vector components with subscripts as is conventional. To avoid confusion between subscripts and variable names, use strings for the subscripts:
fVector = Array[Subscript[f, {"x", "y"}[[#]]][x, y] &, 2]
Then form the Jacobian and display it in TraditionalForm
:
D[fVector, {{x, y}}] // MatrixForm // TraditionalForm
The result is as shown above.
Edit
In this answer to How to make traditional output for derivatives I posted a newer version of the derivative formatting that contains an InterpretationFunction
which allows you to evaluate the derivatives despite their condensed displayed form.