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Graphics[KnotData[{5, 1}, "KnotDiagramData"]] gives

but I would like to create diagrams like this

remeniscent of Celtic knot designs (which I made by adapting the above Mathematica image in Illustrator). Is there any way to do this in Mathematica directly?

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2 Answers 2

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You can use a common 3D trick with double boundary (1, 2, 3): 

fun = KnotData[{5, 1}, "SpaceCurve"];
ParametricPlot3D[fun[t], {t, 0, 2 Pi}, PlotPoints -> 100, MaxRecursion -> 1, 
   Axes -> False, Boxed -> False, ViewPoint -> {0, 0, ∞}, 
   ViewVertical -> {0, -1, 0}, PlotRange -> All, 
   Lighting -> {{"Ambient", White}}] /. 
  Line[pts_] :> {White, Tube[pts, 0.1], FaceForm[Opacity[0], Black], 
    Tube[pts, 0.12]}

enter image description here

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  • $\begingroup$ Nice solution thanks! :) One minor poit - mine is showing up slightly differently to youur - ie with contour lines - I an on v.10.2 - can you relpicate this? $\endgroup$
    – martin
    Commented Nov 15, 2015 at 15:49
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    $\begingroup$ @martin It is a bug of versions 10.0 – 10.2, I advise to upgrade to 10.3. $\endgroup$
    – ybeltukov
    Commented Nov 15, 2015 at 16:10
  • $\begingroup$ ok will do - thanks again :) $\endgroup$
    – martin
    Commented Nov 15, 2015 at 16:13
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This is only a first idea how one could proceed

KnotData[{5, 1}, "Name"]

"Solomon seal knot"

fun = KnotData["Solomon seal knot", "SpaceCurve"];

par =
 ParametricPlot3D[fun[t], {t, 0, 2 Pi},
  Axes -> False,
  Boxed -> False,
  ViewPoint -> Above,
  ImageSize -> Medium,
  PlotStyle -> Thickness[0.05]]

enter image description here

ColorNegate @ EdgeDetect @ Image @ par

enter image description here

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