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Using 

tmp = ContourPlot[{y^4 + 6 x^3*y + x^8 == 0, y - x^3 == 0}, {x, -5, 
   5}, {y, -5, 5}]

How can I get the pair values used to plot these two curves?

For example: x^2 + y^2 - 1 = 0 , (2,Sqrt(-3)) is a point of the curve.

Thank you.

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  • $\begingroup$ For example, (2,√−3) is a point of the curve defined by x^2 + y^2 − 1 = 0 and the usual unit circle is the real part of this curve. The term "unit circle" may refer to all the complex points as well to only the real points, the exact meaning being usually clear from the context. The equation x^2 + y^2 + 1 = 0 defines an algebraic curve, whose real part is empty. $\endgroup$
    – Luiz Meier
    Commented Aug 16, 2014 at 0:16
  • $\begingroup$ @MichaelE2 : I wish to see the entire set or a part of the pairs (x1,y1) , (xn,yn) of a ContourPlot and not to save it to a file. Thanks. $\endgroup$
    – Luiz Meier
    Commented Aug 16, 2014 at 0:19
  • $\begingroup$ Let me try to explain again: How can I get the values used to plot the two algebraic curves in the original plot? The 'duplicate question' don't have the answer I am asking for. $\endgroup$
    – Luiz Meier
    Commented Aug 16, 2014 at 0:25
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    $\begingroup$ The Cases command in the answer to the duplicate yields the points (pairs) you seek. The answer says nothing about saving to a file -- the Export command is irrelevant. $\endgroup$
    – Michael E2
    Commented Aug 16, 2014 at 0:38
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    $\begingroup$ @LuizRobertoMeier I see, I think: You want the points of intersection? That's not what the question asks as currently stated. $\endgroup$
    – Michael E2
    Commented Aug 16, 2014 at 0:50

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