Post Closed as "Duplicate" by Michael E2, Öskå, RunnyKine, m_goldberg, Dr. belisarius

occurred Aug 16, 2014 at 14:02

added 10 characters in body

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edited Aug 16, 2014 at 0:08

Using

tmp = ContourPlot[{y^4 + 6 x^3*y + x^8 == 0, y - x^3 == 0}, {x, -5, 5}, {y, -5, 5}]

tmp = ContourPlot[{y^4 + 6 x^3*y + x^8 == 0, y - x^3 == 0}, {x, -5, 
   5}, {y, -5, 5}]

How can I get the pair values used to plot these two curves?

For example: x^2 + y^2 - 1 = 0 , (2,Sqrt(-3))x^2 + y^2 - 1 = 0 , (2,Sqrt(-3)) is a point of the curve.

Thank you.

Using

tmp = ContourPlot[{y^4 + 6 x^3*y + x^8 == 0, y - x^3 == 0}, {x, -5, 5}, {y, -5, 5}]

How can I get the pair values used to plot these two curves?

For example: x^2 + y^2 - 1 = 0 , (2,Sqrt(-3)) is a point of the curve.

Thank you.

Using

tmp = ContourPlot[{y^4 + 6 x^3*y + x^8 == 0, y - x^3 == 0}, {x, -5, 
   5}, {y, -5, 5}]

How can I get the pair values used to plot these two curves?

For example: x^2 + y^2 - 1 = 0 , (2,Sqrt(-3)) is a point of the curve.

Thank you.

Source Link

asked Aug 16, 2014 at 0:04

Values of an algebraic curve

Using

tmp = ContourPlot[{y^4 + 6 x^3*y + x^8 == 0, y - x^3 == 0}, {x, -5, 5}, {y, -5, 5}]

How can I get the pair values used to plot these two curves?

For example: x^2 + y^2 - 1 = 0 , (2,Sqrt(-3)) is a point of the curve.

Thank you.

plotting

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