1
$\begingroup$

I am trying to visualize the intersection of a complex curve in $\mathbb{C}^2$ with various 3D subspaces but I am not sure how to get Mathematica to do it (so far I have been able to visualize intersections with 2D subspaces using ReIm and ContourPlot). For example, say I have the curve $p^4+qp^2+1=q^8$ in $\mathbb{C^2}$, how would I get Mathematica to plot all values where $p \in \mathbb{R}$ and $q \in \mathbb{C}$?

Thanks in advance!

$\endgroup$
2
  • $\begingroup$ Can you show an example anywhere from the web or a paper? $\endgroup$ Commented Sep 8, 2023 at 21:02
  • 1
    $\begingroup$ People here generally like users to post code as copyable Mathematica code as well as images or TeX, so they can copy-paste it. It makes it convenient for them and more likely you will get someone to help you. You may find the meta Q&A, How to copy code from Mathematica so it looks good on this site, helpful $\endgroup$
    – Michael E2
    Commented Sep 8, 2023 at 21:25

1 Answer 1

2
$\begingroup$

Using the method in Plotting implicitly-defined space curves

Block[{F},
 F[p_, q_] := p^4 + q*p^2 - q^8 + 1;
 ContourPlot3D[
  ComplexExpand@ReIm@F[pR + I*pI, qR + I*qI] /. pI -> 0 // Evaluate,
  {pR, -4, 4}, {qR, -4, 4}, {qI, -2, 2},
  MaxRecursion -> 3, PlotPoints -> 25,
  Contours -> {0}, ContourStyle -> Opacity[0], Mesh -> None, 
  BoundaryStyle -> {1 -> None, 
    2 -> None, {1, 2} -> {{Green, Tube[.03]}}}, Boxed -> False]
 ]

enter image description here

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.