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I am trying to run FindClusters[hex, DistanceFunction -> HammingDistance[IntegerDigits[#, 2, 8], IntegerDigits[0, 2, 8]] &] over a list of data but I keep getting the error enter image description here

(the number of cluster DistanceFunction ... can only be either a positive integer or automatic)

There is no problem running FindClusters[hex] or FindClusters[hex, DistanceFunction -> CanberraDistance]

I have also tried using DistanceFunction -> HammingDistance[BaseForm[#, 2], BaseForm[16^^0, 2]] & DistanceFunction -> HammingDistance[#, 16^^0] &

Sort of at a loss as to what to try next. Any suggestions?

My data is just a list of integers. e.g. {85,137,229,...}

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    $\begingroup$ Try scoping the pure function DistanceFunction -> (HammingDistance[IntegerDigits[#, 2, 8], IntegerDigits[0, 2, 8]] &) $\endgroup$
    – Rohit Namjoshi
    Commented Dec 18, 2020 at 17:27
  • $\begingroup$ That did it! Thank you! What is the reasoning for this? $\endgroup$
    – skyfire
    Commented Dec 18, 2020 at 17:57
  • $\begingroup$ I guess as a followup, this puts everything in 1 cluster. Do you know why that may be? $\endgroup$
    – skyfire
    Commented Dec 18, 2020 at 17:59
  • $\begingroup$ Ah nvm just need to put the number of partitions between hex and dist.. $\endgroup$
    – skyfire
    Commented Dec 18, 2020 at 18:07
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    $\begingroup$ @skyfire you ran into an operator precedence issue. I have learned from experience that pure functions given on the right-hand-side of rules / options are best wrapped in ( ) to make sure that the & operator binds to the right thing, i.e. OptionName -> (something something &). $\endgroup$
    – MarcoB
    Commented Dec 18, 2020 at 19:36

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