# How to calculate Inverse Fourier Transform and cancel out things like HeavisideTheta (so, the function looks exactly like the initial notation)

my question has two parts (please check everything for any mistakes):

The Fourier transform of

FourierTransform[Exp[-a Abs[t]], t, ω,
FourierParameters -> {1, -1}]=(2 a)/(a^2 + ω^2)


1.How to get its Inverse Fourier Transform correctly?

InverseFourierTransform[2 a/((a^2) + (ω^2)), ω, t,
Assumptions -> a > 0 , FourierParameters -> {1, -1}]=E^(a t) HeavisideTheta[-t] + E^(-a t) HeavisideTheta[t]


is it correct?

1. How to display the Inverse Fourier Transform without any HeavisideTheta?(or anything else which makes the answer different from the initial function) so the answer looks like the initial theoretical notation: Exp[-a Abs[t]].

Thanks

\$Version

"12.1.0 for Mac OS X x86 (64-bit) (March 14, 2020)"

Clear["Global*"]

expr = Exp[-a Abs[t]];

ft = FourierTransform[expr, t, ω, FourierParameters -> {1, -1}]

(* (2 a)/(a^2 + ω^2) *)

ift[t_] = InverseFourierTransform[ft, ω, t, Assumptions -> a > 0,
FourierParameters -> {1, -1}]

(* E^(a t) HeavisideTheta[-t] + E^(-a t) HeavisideTheta[t] *)


Since HeavisideTheta is undefined at zero, the ift is equal to expr everywhere except for t == 0.

Simplify[expr == ift[t], #] & /@ {t < 0, t == 0, t > 0}

(* {True, 2 HeavisideTheta[0] == 1, True} *)


This is due to the fact that expr is not smooth for t == 0

Plot[expr /. a -> 1, {t, -3, 3}]


EDIT: For FourierParameters -> {1, -1}] the InverseFourierTransform is given by

ift[t_] = 1/(2 Pi) Integrate[
ft E^(I ω t), {ω, -Infinity, Infinity},
Assumptions -> {a > 0, Element[t, Reals]}]

(* E^(-a Abs[t]) *)

ift[t] == expr

(* True *)

• what should I add to the InverseFourierTransform to not calculate for t=0? May 11, 2020 at 15:59
• InverseFourierTransform does not calculate the inverse for t == 0 since the inverse is not defined there. If you want to define ift at zero, use Limit, i.e., ift[0] = Limit[ift[t], t -> 0] May 11, 2020 at 17:02
• Yeah, I got that part, but please just mention this how can I recreate the exact initial function Exp[-a Abs[t]]` ? May 11, 2020 at 17:09