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I have a 2D list of values that I want to transform/calibrate to another 2D list. I thought of using a predict function but I couldn’t get it to output 2 values.

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I have a list of 2D coordinates {x1, y1}, {x2, y2}, {x3, y3}, etc.. and need to find a method/function/model to turn them into {a1, b1}, {a2, b2}, {a3, b3}...

For instance: {101, 50}, {210, 55}, {305, 47} translates into {0, 1}, {1, 1}, {2, 1}.

Once the function is calibrated to the control set i will apply it to another set of points to use the same transformation

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    $\begingroup$ Not enough information, by a long shot. Show the list you have, show the kind of transformation you would like to apply, etc etc. $\endgroup$
    – MarcoB
    Commented Nov 20, 2019 at 18:23
  • $\begingroup$ Updated the question $\endgroup$ Commented Nov 20, 2019 at 18:50
  • $\begingroup$ could you please provide access to the entire dataset via pastebin.com or such, because as presented you would probably want to use 2 Predict calls to generate 2 PredictorFunction, one for xi->ai and one for yi->bi $\endgroup$ Commented Nov 20, 2019 at 19:18

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You could use a neural network. The architecture needed will depend on the specifics of the data and the domain. In this simple example a single LinearLayer is used.

in = {{101, 50}, {210, 55}, {305, 47}};
out = {{0, 1}, {1, 1}, {2, 1}};
trainingData = Thread[in -> out];

nn = NetInitialize@NetChain[{LinearLayer[]}, "Input" -> 2, "Output" -> 2]
net = NetTrain[nn, trainingData]

net[{300, 50}]
(* {1.91802, 1.01347} *)
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  • $\begingroup$ Hi Rohit... thanks for that... could you help me add a BasicRecurrentLayer to that? Cuz I’m trying to get my head around it and failing miserably. $\endgroup$ Commented Nov 22, 2019 at 17:52
  • $\begingroup$ @CuriousDudeFromEgypt You are welcome. Why does mapping the coordinate pairs need a BasicRecurrentLayer? Probably best if you created a new post with more details about the data, what you are trying to accomplish and any code you have tried. $\endgroup$ Commented Nov 23, 2019 at 1:58
  • $\begingroup$ Hi Rohit, it probably doesn’t... but I thought I do it as well just to learn how to use the BasicRecurrentLayer because I cannot get my head around its input/output matrix requirements.... $\endgroup$ Commented Nov 23, 2019 at 8:27
  • $\begingroup$ @CuriousDudeFromEgypt Ah, in that case take a look at the Application section in the docs for BasicRecurrentLayer. There is also this great video on RNN's. $\endgroup$ Commented Nov 23, 2019 at 22:37

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