You can see that there are gaps on all sides of the plot between the frame and the extent of the line that I've plotted. How do I get rid of these? I'd like the frame to cover $[0,1]\times[0,1]$ and no more.

Plot[x, {x, 0, 1}, Frame -> True]

enter image description here

  • $\begingroup$ One way is to specify PlotRange as in Plot[x, {x, 0, 1}, Frame -> True, PlotRange -> {{0, 1}, {0, 1}}]. $\endgroup$ Jan 31, 2013 at 12:57
  • $\begingroup$ @b.gatessucks This also works; thanks! $\endgroup$ Jan 31, 2013 at 13:22
  • $\begingroup$ Related: (3618), (7453), (9346) $\endgroup$
    – Mr.Wizard
    Mar 7, 2017 at 6:23

1 Answer 1

Plot[x, {x, 0, 1}, Frame -> True, PlotRangePadding -> 0]

Mathematica graphics

The key to the solution was PlotRangePadding -> 0.

  • $\begingroup$ Whoops, I missed that. I was looking for options relating to Frame. Thanks! $\endgroup$ Jan 31, 2013 at 13:21
  • 1
    $\begingroup$ @Will I understand; there are a lot of options, especially for plotting and graphics. $\endgroup$
    – Mr.Wizard
    Jan 31, 2013 at 13:29
  • $\begingroup$ PlotRangePadding->0 did not quite eliminate the white space in my ContourPlot and StreamPlot, but PlotRangePadding->-0.02 did. $\endgroup$ Apr 18, 2017 at 0:39
  • $\begingroup$ @Sander That's a bit unexpected in the case of ContourPlot; which version are you using, and is it with every plot or specific code? StreamPlot does seem to leave some extra space so a negative padding value makes more sense there. $\endgroup$
    – Mr.Wizard
    Apr 18, 2017 at 6:20
  • $\begingroup$ @Mr.Wizard You are right, the ContourPlot on its own does not leave white space with 0 padding. The white space on it was due to overlaying with the previous StreamPlot using Show[]. I guess it inherited the StreamPlot's padding. $\endgroup$ Apr 20, 2017 at 1:52

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