How can I plot two equations in one 3D graph. I have to plot x^2+y^2=1 and x^2+y^2+z^2=2 but I want tu plot only their intersection :(
Thank you
2
-
$\begingroup$ There were many similar questions so most likely this is a duplicate e.g. take a look at this : mathematica.stackexchange.com/questions/5968/…. Perhaps another hint : mathematica.stackexchange.com/questions/17799/… $\endgroup$– ArtesCommented Apr 20, 2013 at 12:20
-
$\begingroup$ You are plotting x^2 + y^2 = 1. That's the unit circle. The second equation says 1+z^2=2, so z^2=1. Assuming we're talking about real numbers, this means either z=1 or z=-1. So your plot is: a unit circle at z=1 and another unit circle at z=-1. $\endgroup$– bill sCommented Apr 20, 2013 at 12:42
Add a comment
|
1 Answer
$\begingroup$
$\endgroup$
Using the first link provided by Artes in the comments:
ContourPlot3D[{x^2 + y^2 - 1, x^2 + y^2 + z^2 - 2},
{x, -2, 2}, {y, -2, 2}, {z, -2, 2},
ContourStyle -> None, Mesh -> None,
BoundaryStyle -> {1 -> None, 2 -> None, {1, 2} -> Black}]
