2
$\begingroup$

I have the following code:

Inv=WeierstrassInvariants[{1,I/3}]

Plot[Re[WeierstrassP[2*x + 1 + I/3, Inv]], {x, 0, 1/2}, WorkingPrecision -> 10]

and I have completely blank plots. Increasing the value of WorkingPrecision also doesn't change anything. To the contrary, not using WorkingPrecision produces a plot. Is there something I'm overlooking here? I can use WorkingPrecision to plot simple functions, but I have yet to get it to work with Weierstrass-$\wp$ despite lots of work.

$\endgroup$
  • $\begingroup$ Welcome to Mathematica.SE! I suggest the following: 0) Browse the common pitfalls question 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Read the faq! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign! $\endgroup$ – Dr. belisarius Jul 24 '15 at 3:45
  • $\begingroup$ But what are you trying to achieve with your setting of WorkingPrecision, especially since you are reducing it from the default? $\endgroup$ – MarcoB Jul 24 '15 at 4:02
  • $\begingroup$ @MarcoB I had no idea I was reducing it. Is it because I don't have any decimals in the input? Sorry, I'm completely new to even basic numerics. $\endgroup$ – Benighted Jul 24 '15 at 4:44
  • $\begingroup$ For a starter, take a look at this tutorial: Control the Precision and Accuracy of Numerical Results $\endgroup$ – MarcoB Jul 24 '15 at 5:00
3
$\begingroup$
Inv = WeierstrassInvariants[{1, I/3}];
Plot[Re[N[WeierstrassP[2*x + 1 + I/3, Inv], 100]], {x, 0, 1/2}, WorkingPrecision -> 100]

Mathematica graphics

$\endgroup$
  • $\begingroup$ Right, that's precisely what I get too but that's without using WorkingPrecision. With WorkingPrecision, I get nothing. $\endgroup$ – Benighted Jul 24 '15 at 3:55
  • $\begingroup$ @spietro See edit $\endgroup$ – Dr. belisarius Jul 24 '15 at 4:23

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.