To see why this happened, we can firstly factor the polynomial in $\mathbb{Q}$.
Factor[x^16 + x^3 + x + 1]
(1 + x) (1 - x + x^2) (1 + x - x^4 + x^7 - x^10 + x^13)
So -1 is a real root. The roots of 1 - x + x^2
are complex, now we consider the last polynomial. We need The Fundamental Theorem of Algebra:
Every $f\in\mathbb{R}[x]$ of odd degree has at least one root in $\mathbb{R}.$
The function CountRoots
can give the number of real roots of a polynomial.
CountRoots[1 + x - x^4 + x^7 - x^10 + x^13, x]
1
The origin polynomial has two real roots, i.e. one is -1, the other is the real root of 1 + x - x^4 + x^7 - x^10 + x^13
. But because of the Galois Theory the polynomial of degree greater than 4 is not solvable by radical. In Mathematica the roots of a polynomial with degree $>4$ are usually expressed as Root[poly,k]
. You can easily verify that when k=1
the root is real.