I have NDSolve` StateData from an NDSolve` ProcessEquations evaluation. I can NDSolve` Iterate from t0 to t1, but then my boundary condition (an interpolation function) runs out of data.

This interpolation function gets updated externally. I just want to continue iterating (t1 to t2) with the updated interpolation function. However, calling myStateData@"NumericalFunction" shows that NDSolve holds onto the old interpolation function, even though this function is defined with a delayed set i.e. myInterpFunction[t_]:=something[t]

Is there any way to update the functions inside of the state data?

Here is a simplified version of what I'm doing:

myStateData = NDSolve`ProcessEquations[
    (*boundary conditions*)
    T[xf, t] == myInterpolationFunction[t],
    T[0, t] == 0,
    (*Initial condition*)
    T[x, t0] == initialCondition[x]};
    T, t, {x, 0, xf}]

Then I need to solve so...


Then externally I update my boundary condition so that now it goes to t2 but when I evaluate


Mathematica returns an error saying that the interpolation function doesn't cover that range (t1 - t2) because it's holding onto the old interpolating function. In other words, looking at


shows myInterpolationFunction has a domain of {t0,t1}

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    – bbgodfrey
    Apr 12, 2015 at 19:42
  • $\begingroup$ Please include your actual code, or a simplified version of it if practical, so that readers can understand what you are doing. $\endgroup$
    – bbgodfrey
    Apr 12, 2015 at 19:43
  • $\begingroup$ I've added simplified code. My interpolation function is good from "t0" to "t1", once I update the function to go to "t2" I need NDSolve to continue Iterating/integrating to t2 $\endgroup$ Apr 12, 2015 at 19:51
  • $\begingroup$ Try myInterpolationFunction[t_?NumericQ] := something[t]. See also mathematica.stackexchange.com/questions/18393/… $\endgroup$
    – Michael E2
    Apr 12, 2015 at 21:12
  • 1
    $\begingroup$ (If you did try it and it did not work, then I suggest it is because the problem is not sufficiently described in the question. There must be something in the missing details that causes an unanticipated problem.) $\endgroup$
    – Michael E2
    Apr 13, 2015 at 2:10