I have the following input form:
R[η_] := (3*Subscript[ρ, B]*aEta[η]^-3)/(4*Subscript[ρ, γ]*aEta[η]^-4)
It's supposed to look like this: $$R[\eta\_]:=\frac{3 \rho_B\space a_{\eta}[\eta]^{-3}}{4\space\rho_{\gamma}\space a_{\eta}[\eta]^{-4}}$$ But when I convert it to Normal Form, Mathematica attempts to simplify the negative powers and I get: $$R[\eta\_]:= \frac{3\rho_B}{\frac{a_{\eta}[\eta]^3(4\rho_{\gamma})}{a_{\eta}[\eta]^4}}$$ Is there anyway to force the Standard Form to show the way it's supposed to look (i.e. the way the formula is traditionally written in the textbooks). Perhaps some association operator that can't be overridden when converting from Input to Standard?
aEta
$\endgroup$Power
typeset in StandardForm and the other twoPower
left alone. Examine carefullyHold[ R[\[Eta]_] := (3*Subscript[\[Rho], B]*aEta[\[Eta]]^-3)/(4* Subscript[\[Rho], \[Gamma]]*aEta[\[Eta]]^-4) ] // FullForm
and note the form of the RHS isnum * Power[den, -1]
. I'd try entering the definition using control-/
. $\endgroup$