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Consider the following:

cacl = Molecule[{Atom["Ca"], Atom["Cl"]}, {Bond[{1, 2}, "Single"]}];
MoleculeValue[cacl, "CanonicalSMILES"]
(* Cl[CaH] *)

Notice the artificial insertion of the hydrogen atom to fill the valency of the calcium atom. I understand that this behaviour is mentioned in the official documentation:

"Hydrogen atoms may be omitted from the atom list if their presence can be inferred from the valence and bonding of the atoms present."

But is there a way to suppress this default behaviour? I want the SMILES representation of the molecule above to be Cl[Ca+], not Cl[CaH].

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  • $\begingroup$ Unfortunately, there seems to be no way. I think this choice of default behaviour was a very short-sighted decision on the part of Wolfram Research. $\endgroup$ – Shredderroy Oct 8 at 16:34
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I imagine it's because CaCl is not a valid compound. If you want CaCl+, you can do:

cacl = Molecule[{Atom["Ca+"], Atom["Cl"]}, {Bond[{1, 2}, "Single"]}]

enter image description here

MoleculeValue[cacl, "CanonicalSMILES"]

"Cl[Ca+]"

For CaCl2:

cacl2 = Molecule[{Atom["Ca"], Atom["Cl"], Atom["Cl"]}, {Bond[{1, 2}, "Single"], Bond[{1, 3}, "Single"]}];
MoleculeValue[cacl2, "CanonicalSMILES"]

"Cl[Ca]Cl"

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You can use a SMILES string to create the molecule. In a SMILES string, wrapping an atomic symbol with brackets signifies that there should be no implicit hydrogens added.

mol = Molecule["[Ca][Cl]"]

enter image description here

Note that this does leave an unpaired electron on the calcium atom,

In[17]:= AtomList@mol

Out[17]= {Atom["Ca", "UnpairedElectronCount" -> 1], Atom["Cl"]}

which I think is what you are going for.

I think a reasonable way to input atoms like this would be something like

Molecule[{"[Ca]", "Cl"}, {Bond[{1, 2}, "Single"]}]

I can make the above work for 12.1

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  • $\begingroup$ Perhaps explicitly indicating the formal charge of a specific atom might be sufficient? $\endgroup$ – J. M. will be back soon 12 hours ago

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