4
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I have the following code:

f[u_] = Graphics[{Circle[{0, 1}, 1],  Circle[{2 Sqrt[u], u}, u]}]
Manipulate[Show[f[u]], {{u, 0.5},1,10}]

Now, if we try the slider, we can actually see that when we make the second circle (the one for which its center and radius depend on $u$), the first "fixed" circle (the unit circle centered in $(0,1)$) will shrink in size in the picture.

What should I do in order to keep that circle "fixed" in size, i.e. no matter how big I make the second circle, the first circle remains fixed in size when using the slider? (so the image does not zoom in/out to see both circles)

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1
  • $\begingroup$ Add an appropriate fixed PlotRange to your Show? $\endgroup$
    – MarcoB
    Mar 27, 2019 at 21:24

1 Answer 1

3
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Try something like this:

ClearAll[f]
f[u_] := Graphics[{Circle[{0, 1}, 1], Circle[{2 Sqrt[u], u}, u]}]
Manipulate[
 Show[
   f[u], 
   PlotRange -> PlotRange[f[10]], 
   PlotRangePadding -> Scaled[.05]
 ],
 {{u, 0.5}, 0.5, 10}
]

Here I use the PlotRange function to extract the plot range for the graphic with the largest possible circle, i.e. the one produced by f[10], then apply 5% padding to that range to make sure that everything fits comfortably.

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2
  • $\begingroup$ This is exactly what I needed! Thank you! $\endgroup$
    – QWE
    Mar 27, 2019 at 21:28
  • $\begingroup$ @QWE Glad to help! You are very welcome. $\endgroup$
    – MarcoB
    Mar 27, 2019 at 21:28

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