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I have 2 equations that I want to equate to each other and solve for a certain variable in one of the equations. 

(1/a)-(b*e^-2a)/a= -(e^-2a*V0)/a

I want to find a general expression for V0 where a and b are constants. Can someone give me a little nudge in the right direction? How do I tell mathematica that I want to solve for v0? I know it treats a & b as constants by default.

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    $\begingroup$ Note that if e is intended to be the exponential constant then it should be entered as E $\endgroup$
    – Bob Hanlon
    Commented Sep 10, 2018 at 20:51

2 Answers 2

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Solve[1/a - (b e^-2 a)/a == -(e^-2 a V0)/a, V0][[1]]

$$\left\{\text{V0}\to \frac{a b-e^2}{a}\right\}$$

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Another possible interpretation:

Solve[1/a - (b E^-(2 a))/a == -(E^(-2 a) V0)/a, V0]

{{V0 -> b - E^(2 a)}}
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