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I want to plot x = u Cos[Phi] + v Cos[(u Phi)/v] and y = u Sin[Phi] - v Sin[(u Phi)/v]in a parametric graph for u = 3 and v = 5. This is my command: 

ParametricPlot[{x, y} /. {u -> 3, v -> 5}, {Phi, 0, 2 Pi}, 
 PlotRange -> All]

I think it was supposed to show two circles and it's not.

Also, for the same u and v values, if the angular velocity of the inner circle about its own center is 0.1 rad/sec, and the time taken for an arbitrary initial contact point to return to the same con figuration.

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    $\begingroup$ Definitely not a circle. $\endgroup$
    – march
    Commented Apr 15, 2016 at 5:31
  • $\begingroup$ Hmm that's what I thought too. But then the problem asks what are the radii for the inner and outer circles so I'm not sure $\endgroup$
    – Ccyan
    Commented Apr 15, 2016 at 5:40

1 Answer 1

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p1 = ParametricPlot[{x, y} /. {u -> 3, v -> 5}, {Phi, 0, 10 \[Pi]}, 
PlotRange -> All]

enter image description here

v=2;

p2 = ParametricPlot[{v Cos[u], v Sin[u]}, {u, 0, 2 Pi}, 
PlotStyle -> Directive[Red, Opacity[1]]]

enter image description here

Show[p1, p2]

enter image description here

but do the Math by your self, because there are other circles

Edit - some sources and infos:

Parametric Equations

Natural Parametric Equations

Circle

How to | Plot Parametric Functions

How to | Create Plots

Have Fun!

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  • $\begingroup$ What do you mean other circles? And why did you use sin and cos to get the circle? I really don't get this $\endgroup$
    – Ccyan
    Commented Apr 15, 2016 at 6:04

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