If I want to calculate with units, for example using Pythagoras theorem, I would do this:
c = Sqrt[(3m)^2 + (5m)^2]
The result will be 5 Sqrt[m^2]
.
How can I define that m = Sqrt[m^2]
and so forth?
Take a look at this blog post by Jon McLoone:
Automatic Physical Units in Mathematica
where he explains how to use this package:
which has over 1000 physical units. Also you can simply use Wolfram|Alpha integration in Mathematica. At the beginning of any input line type single equal sign and see it turn into a large orange equal sign, - then compute:
Using little plus sign at the top right corner you can do more complicated things, like mixed units computation for mechanical kinetic energy below, giving correct units of Joules:
Typing equal sign twice you can get a full Wolfram|Alpha query in your notebook with more relevant info:
Assuming[m > 0, Simplify[Sqrt[(3 m)^2 + (5 m)^2]]]
Sqrt[34] m
Or, if you want to have this assumption during your whole session you could define:
$Assumptions = {m > 0};
Now Simplify
and any other function accepting the Assumptions
option will use this assumption:
Simplify[Sqrt[(3 m)^2 + (5 m)^2]]
Sqrt[34] m
PowerExpand[]
would also be useful here.
$\endgroup$
Commented
Aug 29, 2012 at 11:11