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and would wish to reduce them such that they have the same data. 

In[1329]:= Dimensions[NewMeanA]

Out[1329]= {6200, 2}

In[1330]:= Dimensions[NewMeanB]

Out[1330]= {12400, 2}

How can reduce NewMeanB to the size of 6200 or change NewMeanA to 12400 and not affecting the calculated mean values? Appreciate some help here. Thank you.

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    $\begingroup$ ArrayResample might do what you're looking for. $\endgroup$
    – Carl Lange
    Commented Mar 29, 2019 at 9:27
  • $\begingroup$ Thank you i will give it a try. $\endgroup$
    – ljsg
    Commented Mar 29, 2019 at 9:29
  • $\begingroup$ If you want to combine the meanvalues m1=Mean [data1,n1 ] and m2=Mean [data2,n2 ] the combined meanvalue is m=(n1 m1+n2 m2)/(n1+n2) $\endgroup$
    – Ulrich Neumann
    Commented Mar 29, 2019 at 9:36

1 Answer 1

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You could just double every element in NewMeanA to extend it so that it has the same dimensions as NewMeanB:

NewMeanA2 = Join @@ Transpose @ {NewMeanA, NewMeanA};
Dimensions[NewMeanA2]
Mean[NewMeanA] == Mean[NewMeanA2]
(* {12400, 2} *)
(* True *)
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