9
$\begingroup$

I'm working on a special algorithm to implement a more accurate effective mass calculation for hole carriers in silicon in Mathematica. This rather involved algorithm uses incomplete Fermi-Dirac Integrals of the form:

$$\mathscr F_j(x,b)=\frac1{\Gamma(j+1)}\int_b^\infty \frac{t^j}{e^{t-x}+1}\mathrm dt$$

Fincomplete[j_, x_, b_] :=1/Gamma[j + 1] Integrate[t^j/(E^(t - x) + 1), {t, b, ∞},
                                                   Assumptions -> j > 0]

A call to this function with $b=0$ yields the complete Fermi-Dirac integral representation by the nicely implemented PolyLog function within Mathematica:

In[1]:=  Fincomplete[j, x, 0]
Out[1]:= -PolyLog[1 + j, -E^x]

However, if one wants to evaluate the incomplete Fermi-Dirac integral, the expression stays unevaluated, indicating that there is no straightforward solution available.

In[2]:=  Fincomplete[j,x,b]
Out[2]:= Integrate[t^j/(1 + E^(t - x)), {t, b, ∞}, Assumptions -> j > 0]/Gamma[1 + j]

Now, my question(s):

  1. Any idea which of the multitude of mathematical functions within Mathematica could be leveraged to implement the incomplete Fermi-Dirac integral? Could the Nielsen generalized polylogarithm function mentioned within the Mathematica help system be of any service?

  2. Does anybody have this integral already implemented? There are some series expansions quoted on the web, e.g. Computation of the complete and incomplete Fermi-Dirac integral. However, the reference quotes that the series expansions converge rather slowly, and I would like to leave the implementation of the reference above as last resort, since this would take some time and maybe there is an easier way in Mathematica?

Thanks in advance for all of your help!

$\endgroup$
3
  • $\begingroup$ "Could the Nielsen generalized polylogarithm function mentioned within the Mathematica help system be of any service?" - so far as I can tell, no; there isn't a straightforward relationship between the incomplete FD integral and Nielsen's polylogarithm. $\endgroup$ Commented Oct 29, 2012 at 1:32
  • $\begingroup$ Anyway, if you're looking for quick-and-dirty numerical evaluation, you can use NIntegrate[] for the purpose. Method -> "DoubleExponential" is particularly convenient for the task. $\endgroup$ Commented Oct 29, 2012 at 1:44
  • $\begingroup$ "Does anybody have this integral already implemented?", yes, partially here: gnu.org/software/gsl/manual/html_node/… $\endgroup$
    – alfC
    Commented Oct 14, 2014 at 21:34

1 Answer 1

6
$\begingroup$

As I've noted in the comments, you can do a quick-and-dirty implementation using NIntegrate[] with the option setting Method -> "DoubleExponential":

FermiDiracF[j_, x_] := FermiDiracF[j, x, 0];

FermiDiracF[j_, x_, b_] := 
 Module[{prec = Precision[{j, x, b}], bn, jn, mp, tmp, xn},
       mp = TrueQ[prec === MachinePrecision]; If[mp, prec = $MachinePrecision];
   {jn, xn, bn} = SetPrecision[{j, x, b}, prec + 5];
   tmp = Quiet[
          NIntegrate[t^jn/(E^(t - xn) + 1), {t, bn, Infinity},
                     Method -> "DoubleExponential", WorkingPrecision -> prec]/jn!,
          {NIntegrate::inum, NIntegrate::ncvi, NIntegrate::slwcon, NIntegrate::rnderr}];
   If[! FreeQ[tmp, NIntegrate], Return[$Failed]]; If[mp, N[tmp], tmp]] /;
 Positive[j] && (InexactNumberQ[j] || InexactNumberQ[x] || InexactNumberQ[b])

Some sample plots:

Plot[Table[FermiDiracF[j, 2, b], {j, {1/3, 1/2, 1, 3/2, 2, 3}}] // Evaluate, {b, 0, 7}]

plots of various incomplete Fermi-Dirac functions

Plot3D[FermiDiracF[3/2, x, b], {x, -5, 5}, {b, 0, 10}, PlotRange -> All]

surface plot of incomplete Fermi-Dirac function

$\endgroup$
3
  • $\begingroup$ (One can of course do something similar for incomplete Bose-Einstein integrals...) $\endgroup$ Commented Oct 29, 2012 at 3:15
  • $\begingroup$ Is this better than just evaluating N[PolyLog[...]]? $\endgroup$
    – alfC
    Commented Oct 14, 2014 at 21:32
  • 1
    $\begingroup$ PolyLog[] is useful for the complete integrals. The incomplete integrals do not admit a polylogarithmic representation, AFAIK. $\endgroup$ Commented May 1, 2015 at 19:31

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.