Timeline for Can Reduce *really* not solve for x here?
Current License: CC BY-SA 3.0
14 events
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| Apr 13, 2017 at 12:56 | history | edited | CommunityBot |
replaced http://mathematica.stackexchange.com/ with https://mathematica.stackexchange.com/
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| Jul 31, 2012 at 16:04 | comment | added | Artes | @GlenWheeler Ok, thanks. Although that would be a really broad issue if not restricted to a specific equation. | |
| Jul 31, 2012 at 15:33 | vote | accept | Glen Wheeler | ||
| Jul 31, 2012 at 15:33 | comment | added | Glen Wheeler | Of course. I have no idea why I didn't accept it sooner. | |
| Jul 26, 2012 at 9:50 | comment | added | Artes | @GlenWheeler May I ask if my answer satisfies your needs ? | |
| May 6, 2012 at 19:21 | history | edited | Artes | CC BY-SA 3.0 |
More detailed discussion of the main issue of the question
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| Apr 24, 2012 at 18:39 | history | edited | Artes | CC BY-SA 3.0 |
added example of using Reduce with a condition
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| Apr 24, 2012 at 14:46 | comment | added | Szabolcs | @GlenWheeler You may be interested in this blog post to make more sense of the solution that Mathematica returns. You might notice that the solution is just a symbolic representation of the root of the equation you entered near two values. | |
| Apr 24, 2012 at 13:09 | comment | added | Artes |
@MarkMcClure Thank you for your remark, indeed the solutions were represented symbolically with Root, but I meant their values only numerically.
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| Apr 24, 2012 at 12:50 | comment | added | Mark McClure |
@Artes Of course, Mathematica has found exact solutions here; those solutions are just expressed using Root objects. If you plug one of those roots back into the function and use FullSimplify, you get exactly zero.
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| Apr 24, 2012 at 12:43 | comment | added | Artes |
Yes, there are some omissions, however I think both Solve and Reduce are really powerful functions.
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| Apr 24, 2012 at 12:24 | history | edited | Artes | CC BY-SA 3.0 |
added 217 characters in body
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| Apr 24, 2012 at 12:22 | comment | added | Glen Wheeler | I guess it would have been nice for Mathematica to tell me it was having trouble solving for complex x... thanks for the help. | |
| Apr 24, 2012 at 12:17 | history | answered | Artes | CC BY-SA 3.0 |