All Questions
8 questions
0
votes
2
answers
66
views
How do I solve for a variable for a derivative equation?
So I'm entering this as input:
f[p_] := Subscript[l, i] Log[ p] + (N - Subscript[l, i]) Log[1 - p]
f'[p]
...
3
votes
2
answers
258
views
Can Mathematica simplify an ordinary differential equation (ODE) by assuming a power series solution and obtain the recurrence relation?
I have an ordinary differential equation and want to solve it using power series as ψ[x_] = Sum[Subscript[a, n] x^n, {n, 0, ∞}] to obtain the recurrence relation ...
5
votes
3
answers
125
views
Why earlier terms generated from AsymptoticDSolveValue change when increasing the order?
I was comparing my hand solution with Mathematica's. I noticed the particular solution terms generated for a Frobenius series solution change depending on the order. This should not happen. As when ...
3
votes
2
answers
264
views
Series solution of a differential equation
Calculate the series solution of a differential equation:
$\frac{\mathrm{d} y}{\mathrm{~d} x}=-y-x$, ( $\left.y\right|_{x=0}=2$)
AsymptoticDsolvevalue can calculate ...
0
votes
1
answer
239
views
Differentiation of infinite series does not seem to be useful
Trying series solution of differential equations, the routine is to define a function as a series, and differentiate it.
...
4
votes
1
answer
368
views
Finding periodic ODE solution via small parameter method
I want to figure out how to find periodic solutions of ODE via the small parameter method. I will provide couple of examples of what I mean.
Consider equation $\ddot x + 3x = 2 \sin t + \mu \dot x^2$....
1
vote
0
answers
62
views
Numerical Linear response
I have two lists:
the first is {t,f[t]} and the second {t,l[t]}.
What i need is the first order expansion of f[t] in l[t]:
$f(t)\sim f(t)\vert_{l(0)}+\int_{0}^{t}d\tau\; l(\tau)\;\frac{\partial f(t)...
0
votes
0
answers
125
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Series Expansion of Differential Operators [duplicate]
We know about the possibility of series expansion of a function in Mathematica. Same as below, where a function f[a x] is expanded around zero up to 5th order.
<...