How to format convert simple Mathematica expressions into a Maxima-compatible format?

Question

I am trying to compare really long algebraic results from Mathematica with those from Maxima.

Maxima can parse the simplest types of expressions output by Mathematica, such as 2*x+y. But I have results that involve terms like Sqrt[3] and I'd really like more of a "universal" result, e.g., 3^(1/2). That way I can eval_string() in Maxima and compare the two results in Maxima. Similarly, can I format I as %I?

Here is a sample expressions I have:

(1/(320979616137216 z0^6 z1^6))(15552 z0^4 (-9674588160 + 
 53747712 z1^2 - 248832 z1^4 - 2973600 z1^6 - 
 1419008 I Sqrt[3] z1^7 + 1631315 z1^8) + 
72 z0^6 (29023764480 - 1572120576 z1^2 - 642297600 z1^4 - 
 1172903760 z1^6 - 764045056 I Sqrt[3] z1^7 + 1159383225 z1^8) + 
64 z0^7 (9674588160 I Sqrt[3] - 618098688 I Sqrt[3] z1^2 - 
 344818944 I Sqrt[3] z1^4 - 859550688 I Sqrt[3] z1^6 + 
 1550843904 z1^7 + 742039375 I Sqrt[3] z1^8) + 
537477120 z1^4 (-279936 + 
 z1^2 (3888 + 
    z1 (1152 I Sqrt[3] + z1 (-945 - 256 I Sqrt[3] z1)))) - 
35 z0^8 (14511882240 + 
 z1^2 (-1021206528 + 
    z1^2 (-724863168 + 
       55 z1^2 (-43363944 - 24670400 I Sqrt[3] z1 + 
          33942181 z1^2)))) + 
53747712 z0^2 z1^2 (-1679616 + 
 z1^2 (15552 + 
    z1^2 (-2106 + 
       z1 (-736 I Sqrt[3] + z1 (665 + 192 I Sqrt[3] z1))))))