3
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ver1 = 2 x
verf[x_] := ver1
verf[3]

Result : 2 x

Expected Result : 6

In the above code sample, ver1 can change to expressions (4 x + 3,3 x etc)

What is wrong in the code? How can I achieve my objective?

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3
  • 1
    $\begingroup$ Please also see: (11461) $\endgroup$
    – Mr.Wizard
    Oct 10, 2015 at 9:59
  • $\begingroup$ I missed 'Evaluate' in my code .. as suggested by @Enrique Pérez Herrero $\endgroup$ Oct 11, 2015 at 12:53
  • 1
    $\begingroup$ If that is a solution for you simply use = (Set) rather than := (SetDelayed) and leave out Evaluate, for the same effect. I believed that you were looking for a somewhat different evaluation behavior as described in the marked duplicate; even if you are not you may wish to familiarize yourself with that. $\endgroup$
    – Mr.Wizard
    Oct 12, 2015 at 6:59

1 Answer 1

1
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If you do not want to use set delayed in ver1, this is ver1[x_]:= 2 x, you need to evaluate ver1 when verf is defined:

ver1 = 2 x
verf[x_] := Evaluate[ver1]
verf[3]
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