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Given a function f

f=f[x,y,z]

I would like to compute f for different random values of x,y and z greater than 0

x:=RandomReal[n]; y:=RandomReal[n]; z:=RandomReal[n]

say 20 times, and show them as a set, each value of x,y,z and f, I mean something like {x,y,z,f}. I tried 

x:=RandomReal[n]; y:=RandomReal[n]; z:=RandomReal[n]
Do[Print[f[x,y,z]],20]

but it didnt work. As I said, each values of x,y and z must be different, in general.

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  • $\begingroup$ You didn't specify a value for n $\endgroup$
    – Simon Woods
    Commented Sep 25, 2015 at 20:44
  • $\begingroup$ My mistake, let us say n=10. $\endgroup$
    – Patrick El Pollo
    Commented Sep 25, 2015 at 20:52

2 Answers 2

Reset to default
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ClearAll[f]
n = 5
data = RandomReal[n, {20, 3}]
Map[{Sequence @@ #, f @@ #} &, data]
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  • $\begingroup$ It works, thank you. $\endgroup$
    – Patrick El Pollo
    Commented Sep 25, 2015 at 22:44
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Other ways:

f[x_, y_, z_] := z + y + z
r = RandomReal[{0, 1}, {10, 3}];

r /. a : {_, _, _} :> Join[a, {f @@ a}]
r /. a : {_, _, _} :> Append[a, f @@ a]
MapThread[Append, {r, f @@@ r}]
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  • $\begingroup$ It works nicely too. Thanks $\endgroup$
    – Patrick El Pollo
    Commented Sep 25, 2015 at 22:44
  • $\begingroup$ OK, that last one is pretty cool. $\endgroup$
    – Alan
    Commented Sep 26, 2015 at 1:57

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