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The statement Numerator[6/8] evaluates to 3. Numerator[Hold[6/8] does not work. What function NewNumerator[6/8] evaluates to 6?

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    $\begingroup$ Numerator[Unevaluated[6/8]] $\endgroup$
    – ciao
    Commented May 19, 2015 at 18:20
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    $\begingroup$ Why not use Extract[] on the held fraction? $\endgroup$
    – J. M.'s missing motivation ♦
    Commented May 19, 2015 at 18:21
  • $\begingroup$ num[frac_] := frac[[1, 1]] den[frac_] := 1/frac[[1, 2]] num@HoldForm[6/8] den@HoldForm[6/8] $\endgroup$
    – martin
    Commented May 19, 2015 at 20:52

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