4
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I'd like to use StringCount to count the number of subwords in a string that have the form **** where * is designed to stand for any character in a specified set:

starSet = {"A","B","C"};
modifiedStringCount[string,"*****"]

For example:

string = "ABAACAWABCAA";

Would generate an output of 2 if Overlaps -> FALSE and a output of 3 is Overlaps -> TRUE. Is there a way to do this?

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1 Answer 1

Reset to default
1
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starSet = {"A", "B", "C"};
StringCount["ABAACAWABCAA", Repeated[starSet, {5}], 
            Overlaps -> False]

2

Edit:

Alternatives is redundant, see the comment of Sjoerd C. de Vries below. Thanks ;)

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5
  • $\begingroup$ I was trying to find a duplicate but I've failed :/ $\endgroup$
    – Kuba
    Commented Apr 17, 2014 at 11:01
  • 3
    $\begingroup$ I don't think Alternatives is necessary here. A list of patterns is already interpreted as alternatives. See under Details at the StringExpression page. $\endgroup$
    – Sjoerd C. de Vries
    Commented Apr 17, 2014 at 11:11
  • $\begingroup$ @SjoerdC.deVries +1 :) I was not aware of that :) $\endgroup$
    – Kuba
    Commented Apr 17, 2014 at 11:14
  • $\begingroup$ Not everyone is aware of Repeated. Just leave it so. $\endgroup$
    – Sjoerd C. de Vries
    Commented Apr 17, 2014 at 14:49
  • $\begingroup$ @SjoerdC.deVries Ok, will stay then. $\endgroup$
    – Kuba
    Commented Apr 17, 2014 at 14:56

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