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I have drawn a triangle using Line graphics primitive and Graphics3D function:

 Graphics3D[Line[{{1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {1, 0, 0}}], 
 Axes -> False, Boxed -> True, AspectRatio -> 1]

enter image description here

But in the shape I get, the vertices of triangle do not coincide with the vertices of the box, how can I solve this problem?

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    $\begingroup$ I think you can try PlotRangePadding -> 0 $\endgroup$ Commented May 16, 2013 at 5:20

2 Answers 2

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The comment is right, but here is a thought. If you'd like a cube you should use Cuboid and leave the 3D box for the role it plays - to put things in a better 3D perspective (if needed). Then you precisely control all coordinates. You could try something like

Graphics3D[{
  {Red, Opacity[.7], Polygon[{{1, 0, 0}, {0, 1, 0}, {0, 0, 1}}]},
  {Opacity[.2], Cuboid[{0, 1, 0}, {1, 0, 1}]}
  }, Axes -> False, Boxed -> False, AspectRatio -> 1]

enter image description here

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  • $\begingroup$ Very nice, thank you very much. $\endgroup$
    – Ahmad A
    Commented May 16, 2013 at 5:55
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As noted by xslittlegrass you can get coincident vertices by instructing Graphics3D not to use padding of the plot range, by using PlotRangePadding -> 0.

AspectRatio controls the two dimensional image aspect ratio rather the proportions of the three dimensional rendering which is what I expect you intended; for that use BoxRatios.

Specifying Boxed -> True should (by default) produce a graph without axis lines shown, therefore the Axes -> False option is redundant.

Graphics3D[
 Line[Tuples[{0, 1}, 3][[{5, 3, 2, 5}]]],
 Boxed -> True,
 PlotRangePadding -> 0
]

enter image description here

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  • $\begingroup$ Brilliant, thank you very much. $\endgroup$
    – Ahmad A
    Commented May 16, 2013 at 7:16
  • $\begingroup$ @Ahmad You're welcome. $\endgroup$
    – Mr.Wizard
    Commented May 16, 2013 at 7:19

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