1
$\begingroup$

I am unable to simplify this expression, help me in this regard, thanks in advance. I tried this : Normal//ToRadicals//FullSimplify

5 - RootSum[
  5 + 6 #1^2 + 6 #1^3 &, (
   5 Log[1 - #1] - 5 Log[1 - #1] #1 + 11 Log[1 - #1] #1^2)/(
   2 #1 + 3 #1^2) &] + 
 RootSum[5 + 6 #1^2 + 6 #1^3 &, (
   5 Log[-#1] - 5 Log[-#1] #1 + 11 Log[-#1] #1^2)/(2 #1 + 3 #1^2) &]
$\endgroup$
5
  • 1
    $\begingroup$ Did you try N? $\endgroup$
    – user64494
    Nov 3, 2020 at 6:27
  • $\begingroup$ I need a closed-form expression, not a numerical value. $\endgroup$
    – Shivam K
    Nov 3, 2020 at 7:09
  • 2
    $\begingroup$ ComplexExpand[Re[ToRadicals[exp]], TargetFunctions -> {Re, Im}] // Simplify Imaginary part proofs to be zero this way. $\endgroup$
    – Akku14
    Nov 3, 2020 at 8:01
  • $\begingroup$ This is helpful, I got the result, thank you! $\endgroup$
    – Shivam K
    Nov 3, 2020 at 11:03
  • $\begingroup$ @Akku14 Why do not you place your comment as the answer? $\endgroup$ Nov 3, 2020 at 11:17

1 Answer 1

4
$\begingroup$
ComplexExpand[Re[ToRadicals[expr]],TargetFunctions -> {Re, Im}] // Simplify 

Imaginary part proves to be zero this way.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.