I have an expression of the form:

expression = A1*x + A2*x^2 + ...

and I would like to replace A1 by F1[y], A2 by F2[y], etc.

Regular expressions would seem to be the thing to use, but since the above is not a string, I'm not sure how to do this. Would like the solution to be something simple like

expression /. A* :> F*[y]

but of course this doesn't work.

How do I accomplish the above?

  • 3
    $\begingroup$ How are you generating your expression? It might be easier to replace A1,A2,… by A[1],A[2],…. Then, replacement becomes as simple as expression /. A[i_] :> F[i][y]. As a general rule i try to keep any information that I might need again out of symbol names - most function have no issue with composite heads, and it makes extracting the information so much easier $\endgroup$ – Lukas Lang Jan 13 at 18:00
  • $\begingroup$ Yeah that's the problem, the output is from a function in the xAct xTras package and it spits out expressions of the above form with Ai's, rather than A[i]'s. Doesn't seem to be a way of changing it. (MakeContractionAnsatz) $\endgroup$ – user26866 Jan 14 at 18:37

You can use SymbolName to convert symbols to their string names, and then process those strings:

    A1*x + A2*x^2 + A3*x^3,
    s_Symbol :> Module[{n = SymbolName[s]},
        Symbol[StringReplace[n, "A"->"F"]][y] /; StringMatchQ[n, "A"~~DigitCharacter..]

x F1[y] + x^2 F2[y] + x^3 F3[y]

  • $\begingroup$ Beautiful, thanks! $\endgroup$ – user26866 Jan 13 at 19:39

Here is an approach based on string manipulation:

expression = A1 x + A2 x^2 + A3 x^3;

StringReplace[%, "A" ~~ n : DigitCharacter :> "F" ~~ n ~~ "[y]"];

(* x F1[y] + x^2 F2[y] + x^3 F3[y] *)

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