0
$\begingroup$

I am trying to solve a linear differential equation for the change in scale factor term, $\delta a(t)$, when mass terms are introduced to the equations of motion for General Relativity. The first equation I am have to solve is as follows:

$$ \frac{d}{dt} \delta a(t) = \frac{8 \pi G (a(t))^2}{3 \frac{d}{dt}a(t)}[3m^2 (a(t))^2 \mp \frac{1}{2} \delta \rho (t)] + \frac{2\frac{d}{dt}a(t) \delta a(t)}{a} $$ This equation is of the form $\frac{d}{dt} \delta a(t) + f(t) \delta a(t) = g(t)$, which is a linear differential equation.

However, when I plug this equation into Mathematica, using the DSolve function, I receive an error to the degree of

Equation or list of equations expected instead of True in the first argument

My code is as follows:

DSolve[{\[Delta]a'[t] - (2*a'[t]*\[Delta]a[t])/a[t] == (
    8*\[Pi]*G*(a^2)[t])/(
    3*a'[t]) (3*m^2*(a^2)[t] - 1/2 \[Delta]\[Rho][t]), \[Delta]a[0] ==
    0, a[0] == 1}, \[Delta]a[t], t]

where I have introduced the conditions that $\delta a(0) = 0$ and $a(0) = 1$.

What am I doing wrong here, is this just not numerically solvable?

Thanks!

$\endgroup$

1 Answer 1

1
$\begingroup$

Change (a^2)[t] to a[t]^2 and remove the condition a[0] == 1 (NDSolve only accepts initial condition for \[Delta]a[t])

DSolve[{\[Delta]a'[t] - (2*a'[t]*\[Delta]a[t])/a[t] == (8*\[Pi]*G*a[t]^2)/(3*a'[t]) (3*m^2*a[t]^2 - 1/2 \[Delta]\[Rho][t]), \[Delta]a[0] == 0 }, \[Delta]a[t], t]
(*{{\[Delta]a[t] -> a[t]^2 Inactive[Integrate][(2 (12 G m^2 \[Pi] a[K[1]]^5 - 2 G \[Pi] a[K[1]]^3 \[Delta]\[Rho][K[1]]))/(3 a[K[1]]^3 Derivative[1][a][K[1]]), {K[1], 0, t}]}}*)
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.