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   f[x_, y_, z_] := x + Cos[z]^2 + y^2
    ContourPlot3D[f[x, y, z] == 0, {x, -2, 2}, {z, -2, 2}, {y, -2, 2}, 
      Mesh -> {4, 4, 4}] /. Line[p_] :> Tube[p, .1]

In the image we see some nominal Thickness for the surface although no Thickness is specified. It was not bargained for, a sort of non-WYSIWYG situation. We should be able to see through the Tubes to the back side. Can we to do away with it?

If 3d printed, will it print with an arbitrary spurious thickness? Thanks for help.

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  • $\begingroup$ does ContourPlot3D[f[x, y, z] == 0, {x, -2, 2}, {z, -2, 2}, {y, -2, 2}, BoundaryStyle -> None, Mesh -> {4, 4, 4}] /. Line[p_] :> {CapForm["Butt"], Opacity[.5, Red], Tube[p, .1]} give what you need? $\endgroup$ – kglr Aug 12 at 13:37
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Try MeshStyle and MeshStyle

ContourPlot3D[f[x, y, z] == 0, {x, -2, 2}, {z, -2, 2}, {y, -2, 2},Mesh -> {4, 4, 4},MeshStyle -> Opacity[.5],MeshStyle -> None] /. Line[p_] :> Tube[p, .1]

enter image description here

ContourStyle->None only shows the tubes.

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