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Let's take a switch function as an example:
$ u(t)= \begin{cases} 1, & \text{$0<t<dT_s$} \\ 0, & \text{$dT_s<t<T_s$} \end{cases} $
How can I get Fourier series of it in Mathematica?
Is there a way to get Fourier series of arbitrary periodic piecewise function?

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    $\begingroup$ I would start by having a look at Piecewise and Fourier. $\endgroup$ Commented Feb 26, 2019 at 9:09
  • $\begingroup$ @b.gatessucks You probably meant FourierSeries, right? Fourier is the discrete fourier transform (FFT). I am also puzzeld by the many different Fourier-related commands in Mathematica. $\endgroup$ Commented Feb 26, 2019 at 10:11
  • $\begingroup$ @HenrikSchumacher Indeed, thanks for pointing that out. $\endgroup$ Commented Feb 26, 2019 at 10:37
  • $\begingroup$ Strongly related, if not duplicate: mathematica.stackexchange.com/q/149468/1871 $\endgroup$
    – xzczd
    Commented Feb 26, 2019 at 10:39
  • $\begingroup$ People here generally like users to post code as Mathematica code instead of just images or TeX, so they can copy-paste it. It makes it convenient for them and more likely you will get someone to help you. You may find this this meta Q&A helpful $\endgroup$
    – Michael E2
    Commented Feb 26, 2019 at 14:29

2 Answers 2

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for example:

u[t_] = Piecewise[{{1, 0 < t < dT}, {0, dT < t < T}}];
FourierTrigSeries[u[t], t, 3, FourierParameters -> {1, 2 \[Pi]/T}, 
 Assumptions -> 0 < dT < T && 2 dT == T]

enter image description here

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Try u[t_] := UnitStep[Sin[t]]; FourierSeries[u[x], x, 3] 3 is series

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    $\begingroup$ One might want to be mindful of the FourierParameters setting when using FourierSeries[] and other sundry functions, lest Mathematica's chosen normalization might not be the same as your preferred one. $\endgroup$ Commented Feb 26, 2019 at 9:15

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