How can I get what comes out in the image, if possible with the limits of integration.
the solids are for example
$\textbf{x^2+y^2+z^2 =8}$ and $\textbf{z=x^2+y^2}$
I need something like the image, if the integration limits come out better
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1 Answer
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5
r1 = Cylinder[{{0, 0, 0}, {0, 0, 30}}, 12];
r2 = Cylinder[{{-20, 0, 15}, {0, 0, 15}}, 10];
r3 = Cylinder[{{20, 0, 15}, {0, 0, 15}}, 10];
r = RegionUnion[r1, r2, r3];
Region[r]
rr1 = RegionIntersection[r1, r2];
rr2 = RegionIntersection[r1, r3];
rr = RegionUnion[rr1, rr2];
Region[rr, PlotTheme -> "Scientific"]
You can use the regions r and rr inside the integration routine.
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$\begingroup$ Hello I use the version of Mayhematica 10.4, I do not have the commands. What version do you have? $\endgroup$ Commented May 11, 2018 at 3:32
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$\begingroup$ @juanmuñoz Try using
DiscretizeRegioninstead of theRegionfunction. That should be available since v. 10. $\endgroup$– MarcoBCommented May 11, 2018 at 3:52 -
$\begingroup$ @juanmuñoz, I use V11.1. The
Regioncommand just draws the regions defined before. $\endgroup$– Rom38Commented May 11, 2018 at 6:25 -
$\begingroup$ two things The second command served me, but when I made the second order, the video controller went down RAM? On the other hand as it is done with these example solidsthe solids $\textbf{x^2+y^2+z^2 =8}$ and $\textbf{z=x^2+y^2}$ $\endgroup$ Commented May 12, 2018 at 0:19
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$\begingroup$ That's true, the
DiscretizeRegionrequires a lot of memory. You can try to play withMaxCellMeasureoption inside it to decrease the number of polygons in resulting figure. BTW, it is needed only for drawing of figure. You can use therandrrfor calculations $\endgroup$– Rom38Commented May 12, 2018 at 9:26