It appears that Mathematica treats all dates as proleptic Gregorian dates by default, a hypothesis that can be easily tested by using AbsoluteTime
to compute the Julian Day:
jd[t_] := AbsoluteTime[t]/86400 + 2.4150205*^6
but, while this works for recent dates and for some older ones, it yields results that differ from the correct result for some older dates by exactly a day
jd[{2012, 11, 24, 12}] - 2456256
0
jd[{1100, 11, 24, 12, 0, 0}] - 2123154
0
jd[{-3000, 11, 24, 12, 0, 0}] - 625660
1
notably for the reference date, 12:00 Universal Time on January 1, 4713 BCE in the proleptic Julian calendar (-4713-11-24 in the proleptic Gregorian calendar):
jd[{-4713, 11, 24, 12, 0, 0}]
1
What calendar is Mathematica using for these older dates, if not the proleptic Gregorian calendar?
Here, perhaps is another clue:
DateList[{-4713, 11, 24, 12, 0, 0}]
{-4713, 11, 25, 12, 0, 0}
DateList[{-3000, 11, 24, 12, 0, 0}]
{-3000, 11, 25, 12, 0, 0}
I'm no calendar expert, but this "canonicalization" doesn't map to any calendar I'm familiar with. Is this a bug?
Update: Version 9, behaves differently:
jd[{2012, 11, 24, 12}] - 2456256
0.
jd[{1100, 11, 24, 12, 0, 0}] - 2123154
0.
jd[{-3000, 11, 24, 12, 0, 0}] - 625660
365.
jd[{-4713, 11, 24, 12, 0, 0}]
366
and
DateList[{-4713, 11, 24, 12, 0, 0}]
{-4713, 11, 24, 12, 0, 0.}
DateList[{-3000, 11, 24, 12, 0, 0}]
{-3000, 11, 24, 12, 0, 0.}
AbsoluteTime[{2009,01,01,0,0,0}]-AbsoluteTime[{2008,12,31,23,59,59}]
gives1
instead of the correct2
, assuming the standard UTC+Gregorian. $\endgroup$AbsoluteTime[{2009, 01, 01, 0, 0, 0}] - AbsoluteTime[{2008, 12, 31, 23, 59, 59}]
still gives1
, in version 9.0, rather than 2. $\endgroup$DateList
was a bug in version 8. It remains to be seen whyAbsoluteTime
added a day in 8 and a year in 9. $\endgroup$