I want to write function expand[f] which gives the Taylor series expansion of $f(x)$ up to $O(x^4)$ in $\TeX$ form, as well as return the radius of convergence.

I have written:

expand = Function[f, TeXForm[Series[f, {x, 0, 3}]]
SumConvergence[f, x]];

but SumConvergence requires the general term of a sequence, so the syntax written there is incorrect. Is there a command in stead of SumConvergence which will allow me to do this?


As a start on the radius of convergence question:

rc[f_, {x_, x0_}] := Reduce[
      f, {x, x0, \[FormalN]}], \[FormalN] \[Element] Integers && 
      n >= 0] (x - x0)^\[FormalN], \[FormalN]],
  Abs[x - x0]]

Examples. SumConvergence is a bit challenged by SeriesCoefficient tendency to return DifferenceRoot object. FullSimplify helps but is not always sufficient.

rc[1/(4 x^2 + 1), {x, 1}]
(*  Abs[-1 + x] < Sqrt[5]/2  *)

rc[Exp[4 x], {x, 1}]
(*  True  *)

This one needs extra help.

rc[ArcTan[x], {x, 0}]
 FullSimplify[# /. \[FormalN] -> 2 \[FormalN] + 1,
   \[FormalN] \[Element] Integers && n >= 0] &, 
 First[%], 1]

Mathematica graphics

(*  Abs[x] < 1  *)
|improve this answer|||||
expand[f_] := {TeXForm[Series[f, {x, 0, 3}]], SumConvergence[f, x]}



{"1+x \log (n)+\frac{1}{2} x^2 \log ^2(n)+\frac{1}{6} x^3 \log ^3(n)+O\left(x^4\right)",Abs[n]<1}

|improve this answer|||||
  • $\begingroup$ It doesn't work for series like $e^{4x}$. This should converge for all real numbers. $\endgroup$ – Luke Collins Mar 22 '17 at 22:12

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