FindInstance[Sqrt[a x1^2 + b x1 + c] == d x1 + t &&
Sqrt[a x2^2 + b x2 + c] == d x2 + t,
{a, b, c, d, t, x1, x2}, Integers, 10]
(* {{a -> -582, b -> 0, c -> 1, d -> 1, t -> 1, x1 -> 0, x2 -> 0},
{a -> -526, b -> -46, c -> 0, d -> 0, t -> 0, x1 -> 0, x2 -> 0},
{a -> -1, b -> 30, c -> 0, d -> 2, t -> -60, x1 -> 30, x2 -> 30},
{a -> 961, b -> 1, c -> 0, d -> 15, t -> 0, x1 -> 0, x2 -> 0},
{a -> 1, b -> 30, c -> 0, d -> 46, t -> 0, x1 -> 0, x2 -> 0},
{a -> -820, b -> -15, c -> 0, d -> 12, t -> 0, x1 -> 0, x2 -> 0},
{a -> 656, b -> -24, c -> 0, d -> 22, t -> 0, x1 -> 0, x2 -> 0},
{a -> 2, b -> 12, c -> -54, d -> -1, t -> -9, x1 -> -9, x2 -> -9},
{a -> -308, b -> 16, c -> 0, d -> 79, t -> 0, x1 -> 0, x2 -> 0},
{a -> 1, b -> 1, c -> 0, d -> 11, t -> 0, x1 -> 0, x2 -> 0}} *)
If you prefer non-boring solutions: all parameters and solutions shall be non-zero, and $a\neq d^2$ to make sure we have a really quadratic problem:
FindInstance[Sqrt[a x1^2 + b x1 + c] == d x1 + t &&
Sqrt[a x2^2 + b x2 + c] == d x2 + t &&
a != 0 && b != 0 && c != 0 && d != 0 && t != 0 &&
a != d^2 &&
x1 != 0 && x2 != 0 && x1 != x2,
{a, b, c, d, t, x1, x2}, Integers, 10]
FindInstance: Warning: FindInstance found only 9 instance(s), but it was not able to prove 10 instances do not exist.
(* {{a -> -2, b -> -1, c -> 91, d -> 1, t -> 7, x1 -> 2, x2 -> -7},
{a -> -1, b -> -98, c -> 7203, d -> -1, t -> 49, x1 -> -49, x2 -> 49},
{a -> -1, b -> -60, c -> 2700, d -> -1, t -> 30, x1 -> -30, x2 -> 30},
{a -> -1, b -> -10, c -> -8, d -> 1, t -> 10, x1 -> -9, x2 -> -6},
{a -> -1, b -> -6, c -> 55, d -> -1, t -> 5, x1 -> -3, x2 -> 5},
{a -> -1, b -> 8, c -> 42, d -> 1, t -> 6, x1 -> -3, x2 -> 1},
{a -> -1, b -> 54, c -> 2187, d -> 1, t -> 27, x1 -> -27, x2 -> 27},
{a -> 11, b -> -62, c -> 72, d -> -3, t -> 12, x1 -> -9, x2 -> 4},
{a -> 13, b -> 92, c -> 7, d -> 2, t -> 14, x1 -> 3, x2 -> -7}} *)