Function over a list that depends on the index

Question

Suppose I have a list

{a, b, c, d} 

I want to operate on this list with a function which depends on the index of the element, e.g. I want to add the index number to each element to get

{a+1, b+2, c+3, d+4}

what would be the best way to do this?

I have seen some possible approaches but was wondering what the 'canonical' way would be.

Answer 1

MapIndexed:

MapIndexed[#2[[1]] + # &, {a, b, c, d}]

{1 + a, 2 + b, 3 + c, 4 + d}

Also

Range[Length @ #] + # & @ {a,b,c,d}

{1 + a, 2 + b, 3 + c, 4 + d}

Answer 2

A couple more options --

lst = {a, b, c, d};

Table[lst[[n]] + n, {n, Length[lst]}]

{1 + a, 2 + b, 3 + c, 4 + d}

lst + Range[Length[lst]]

{1 + a, 2 + b, 3 + c, 4 + d}

Answer 3

Four more possibilities:

list = {a, b, c, d};

Array[{list[[#]] + #} &, Length @ list]

{{1 + a}, {2 + b}, {3 + c}, {4 + d}}

Module[{i = 1}, # + i++ &] /@ list

{1 + a, 2 + b, 3 + c, 4 + d}

ReplacePart[i_ :> list[[i]] + i] @ list

{1 + a, 2 + b, 3 + c, 4 + d}

Module[{i = 1}, Replace[list, x_ :> x + i++, {1}]]

{1 + a, 2 + b, 3 + c, 4 + d}

Replace can be useful if we want to impose a Condition:

list = {1, 2, 3, Missing[], 4};

Module[{i = 1}, Replace[list, x_Integer :> x + i++, {1}]]

{2, 4, 6, Missing[], 8}