2
$\begingroup$

Find an equation to the tangent of the curve at the given point. Then graph the curve and the tangent.

$$x=t^2-t,\quad y=t^2+t+1; \quad(0,3)$$

I can do this with a simple $f(X)$ function but the parametric curve part is tricky. Any help?

$\endgroup$

3 Answers 3

2
$\begingroup$

This is what I get, but I am not sure. But please check if this is what the final solution should be as I am not too good in calculus. There are two solutions, so I picked the one which goes through (0,3)

ClearAll[x, y, t]
eq1 = x == t^2 - t;
eq2 = y == t^2 + t + 1;
r = Eliminate[{eq1, eq2}, t];
sol = y /. Solve[r, y];
slope = (D[Last@sol, x]) /. x -> 0
eq = TraditionalForm@Row[{"y(x)=", slope*x + 3}];
p1 = Plot[Callout[slope*x + 3, eq, Above], {x, -.5, 1}, PlotStyle -> Red];
p2 = Plot[sol, {x, -2, 2}, Frame -> True, GridLines -> Automatic, 
    GridLinesStyle -> LightGray,BaseStyle -> 14];
Show[p2, p1]

Mathematica graphics

$\endgroup$
5
$\begingroup$
x[t_] = t^2 - t;
y[t_] = t^2 + t + 1;

The value of t for the point {0, 3} is

Solve[{x[t] == 0, y[t] == 3}, t][[1]]

(*  {t -> 1}  *)

The derivative at this point is

y'[t]/x'[t] /. t -> 1

(*  3  *)

Show[
 ParametricPlot[{x[t], y[t]},
  {t, -1, 2}],
 Plot[3 x + 3, {x, -1, 1},
  PlotStyle -> Red],
 AspectRatio -> 1/GoldenRatio]

enter image description here

$\endgroup$
1
$\begingroup$

Tangent

tan[f_, x_: t, scale_: 0.5] := 
 With[{df = D[f, t]}, 
  Arrow[{f, f + scale df / Norm[df]}] /. t -> x]

Normal

nor[f_, x_: t, scale_: 0.5] := 
 With[{df = D[f, t]}, 
  Arrow[{f, f + scale (df /. {a_, b_} :> {-b, a}) / Norm[df]}] /. t -> x]

Symbolic example

tan[{t, t^2}, t, 1]

enter image description here

Numeric example:

tan[{t, t^2}, 0.5, 1]

enter image description here

Plotting is straightforward

g := {t, t^2}

Manipulate[
 ParametricPlot[g, {t, -1, 1},
  BaseStyle -> {PointSize[Large], Thickness[0.005]},
  Epilog -> {Orange, tan[g, n], Blue, nor[g, n], Red, Point[g /. t -> n]},
  PlotRangePadding -> 0.5],
 {n, -1, 1}]

enter image description here

Or use the inbuilt FrenetSerretSystem

tan[f_, x_: t, s_: 0.5] := 
 Arrow[{f, f + s FrenetSerretSystem[f, t][[2, 1]]}] /. t -> x

nor[f_, x_: t, s_: 0.5] := 
 Arrow[{f, f + s FrenetSerretSystem[f, t][[2, 2]]}] /. t -> x
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.