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So I have defined two functions 

s[p_] = -600 + 50 p
d[p_] = 1200 - 25 p

and I want to graph both of them on the same chart using the 

Plot[{50 p - 600, -25 p + 1200}, {x, -10, 10}, PlotLegends → {"Function 1", "Function 2"}]

However, when I evaluate the cells, I get and error saying

Plot::nonopt: Options expected (instead of PlotLegends->{Function 1,Function 2}) beyond position 2 in Plot[{50 p-600,-4 p+1200},{p,-10,10},PlotLegends->{Function 1,Function 2}]. An option must be a rule or a list of rules.

Does anyone know how to fix this?

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  • 1
    $\begingroup$ PlotLegends is obsolete. If you erase this part your function will be drawn $\endgroup$
    – cyrille.piatecki
    Commented Oct 5, 2016 at 5:03
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    $\begingroup$ The problem seems to be with the arrow character (→). Try deleting it and replacing it with ->. $\endgroup$
    – 2012rcampion
    Commented Oct 5, 2016 at 5:22

1 Answer 1

Reset to default
3
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Plot[{50 p - 600, -25 p + 1200}, {p, -10, 10}, 
PlotLegends -> Placed["Expressions", Below]]

or

Plot[{50 p - 600, -25 p + 1200}, {p, -10, 10}, 
PlotLegends -> Placed[{"f1", "g1"}, Below]]
Improve this answer
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1
  • 3
    $\begingroup$ Placed is not necessary; try Plot[{50 p-600,-25 p+1200},{x,-10,10},PlotLegends->{"Function 1","Function 2"}] (the original, but without the → character). $\endgroup$
    – 2012rcampion
    Commented Oct 5, 2016 at 5:23

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