Here is a bit simpler solution with Reverse[data]

ListLinePlot[ Reverse[data],  
              Ticks -> {{Range[20, 100, 10], Range[100, 20, -10]} // Transpose, Automatic}]

Here is a bit different solution

d = Transpose@data;
ListLinePlot[ Transpose@{Reverse@d[[1]], d[[2]]}, 
              Ticks -> {Transpose@{Range[20, 100, 10], Range[100, 20, -10]}, Automatic}]

If we don't like to specify in advance ranges of ticks, here is another, more general approach :

ListLinePlot[ Transpose @ { Reverse@ d[[1]], d[[2]]}, 
              Ticks -> {Transpose @ { Range[ Min[#], Max[#], 
                                     10^(Ceiling@Log[10, (Max[#] - Min[#])] - 1)] &@d[[1]], 
                                     Range[Max[#], Min[#], 
                                     -10^(Ceiling@Log[10, (Max[#] - Min[#])] - 1)] & @ d[[1]]},
                                      Automatic}]

There is no need for options if you make use of Reverse[data]

ListLinePlot[Reverse[data]]

Here is a bit simpler solution with Reverse[data]

ListLinePlot[ Reverse[data],  
              Ticks -> {{Range[20, 100, 10], Range[100, 20, -10]} // Transpose, Automatic}]