Timeline for plotting a trig functions along with its envelope
Current License: CC BY-SA 3.0
18 events
| when toggle format | what | by | license | comment | |
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| May 16, 2015 at 3:25 | history | edited | Mr.Wizard |
edited tags
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| Aug 28, 2014 at 2:24 | comment | added | Mr.Wizard | Also see: (4667323) | |
| Aug 28, 2014 at 0:20 | comment | added | Michael E2 | Nearly a duplicate of Elegant way of obtaining the envelope of oscillating function, which is a duplicate of Mathematica envelope for the bottom of a plot, a generic function. But this one just straight trigonometry. | |
| Jun 4, 2014 at 14:38 | vote | accept | Unbelievable | ||
| Jun 4, 2014 at 3:55 | answer | added | user484 | timeline score: 20 | |
| Jun 4, 2014 at 3:13 | history | edited | m_goldberg | CC BY-SA 3.0 |
Moderate clean-up
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| Jun 3, 2014 at 19:27 | comment | added | Mark McClure | I edited your question. You should make sure that I preserved your intended meaning. | |
| Jun 3, 2014 at 19:26 | history | edited | Mark McClure | CC BY-SA 3.0 |
added 223 characters in body
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| Jun 3, 2014 at 19:05 | review | Close votes | |||
| Jun 3, 2014 at 21:31 | |||||
| Jun 3, 2014 at 18:56 | comment | added | Unbelievable | Ok. I can understand why for every frequency which are different with the one the frequency of the sheath will be 1/2 and for different equal to 2, sheath frequency will be 1 and so on. | |
| Jun 3, 2014 at 18:56 | answer | added | Mark McClure | timeline score: 15 | |
| Jun 3, 2014 at 18:45 | comment | added | Unbelievable | Yes, it was exactly I want. thank you so much. Now, I must think why for every frequency, we can use of the +-2Cos[t/2]. | |
| Jun 3, 2014 at 18:40 | comment | added | Mark McClure | In that case, your sheath is given pretty much perfectly by $\pm 2\cos(t/2)$, but maybe that's not what you want? | |
| Jun 3, 2014 at 18:36 | comment | added | Unbelievable | I plotted these ones with: Plot[{Cos[50 t] + Cos[51 t], Cos[t] + 1.5, -Cos[t] - 1.5}, {t, 0, 10}], I used of simulated functions 'Cos[t] + 1.5' and '-Cos[t] - 1.5' for the sheath. | |
| Jun 3, 2014 at 18:34 | comment | added | Mark McClure | Well, you've got to give us some kind of input to start with. | |
| Jun 3, 2014 at 18:32 | comment | added | Unbelievable | this is completely true but this is for the Fig.1, I want to access to sheath while I do not access to any formula for that. | |
| Jun 3, 2014 at 18:29 | comment | added | Mark McClure |
I'm guessing that's something like Cos[42x]+Cos[43x]?
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| Jun 3, 2014 at 18:27 | history | asked | Unbelievable | CC BY-SA 3.0 |