Timeline for intersection of two lines with a slope slider
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Mar 10, 2014 at 8:41 | vote | accept | Clay | ||
| Mar 10, 2014 at 7:13 | answer | added | ubpdqn | timeline score: 4 | |
| Mar 10, 2014 at 6:55 | comment | added | Andy Mobley | After esprit's fix, you can figure out what the 0.77 should be in terms of formula by setting the IS=LM and then solving for the q that is the intersection of the two lines. You'll find that the ratio q/d at init cond is 0.77. From there you should be able to figure out how to calculate a value for 0.77 that depends upon your variable i and the 0.8 that is in the LM equation. Plug that expression everywhere there is a 0.77. I don't know what that 0.8 means in terms of economics, but it is my guess you will want to be able to vary it as well. Also, your two ranges for q are different. | |
| Mar 10, 2014 at 6:43 | comment | added | qwerty |
The second point in your first Dashed Line should be {0.77*d - (0.77*s), d - i (0.77*d - (0.77*s))}
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| Mar 10, 2014 at 6:14 | comment | added | Andy Mobley |
Glancing at your code, it looks like you are converting a previous static example with specific values for each of d, s, and i to the Manipulate. I think that several of your values that are numerical need to be expressed in terms of your three variables. Specifically I would look at 0.8 (in Plot), the ubiquitous 0.77, and the 0.5 should be i (in first Dashed Line. If you fix those instances with the appropriate formulas, my guess is that most of your worries will be fixed.
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| Mar 10, 2014 at 6:01 | history | edited | m_goldberg | CC BY-SA 3.0 |
Improved formatting
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| Mar 10, 2014 at 5:39 | review | First posts | |||
| Mar 10, 2014 at 6:01 | |||||
| Mar 10, 2014 at 5:21 | history | asked | Clay | CC BY-SA 3.0 |