Timeline for How to find intersecting linear equations between two lists?
Current License: CC BY-SA 4.0
16 events
| when toggle format | what | by | license | comment | |
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| Aug 26 at 4:48 | vote | accept | internet | ||
| Aug 24 at 23:26 | answer | added | cvgmt | timeline score: 3 | |
| Aug 24 at 17:30 | answer | added | ubpdqn | timeline score: 2 | |
| Aug 22 at 21:40 | answer | added | Daniel Lichtblau | timeline score: 4 | |
| Aug 22 at 19:08 | comment | added | Bob Hanlon |
@cvgmt - that appears to be the Union rather than the Intersection
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| Aug 22 at 13:58 | history | became hot network question | |||
| Aug 22 at 9:13 | answer | added | rhermans | timeline score: 3 | |
| Aug 22 at 8:14 | answer | added | Daniel Huber | timeline score: 3 | |
| Aug 22 at 5:56 | comment | added | cvgmt |
The result should be {x - y == 0, x + 2y == 0, 3x - y == 0,3 x - 2 y==0}
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| Aug 22 at 5:08 | comment | added | Bob Hanlon |
SubtractSides /@ Intersection @@ Map[Simplify, {list1, list2}, 2]
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| Aug 22 at 5:06 | comment | added | ydd |
Perhaps something like this? we Or all the equations together and use Reduce to get the reduced set of solutions and then subtract the RHS to get them equal to 0
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| Aug 22 at 5:04 | comment | added | internet | @lericr The equations in my case differ only by flipping the sign of the entire equation and are quite simple, though they involve more variables. Do you think that simplifying them is reliable in this case? | |
| Aug 22 at 4:42 | comment | added | lericr |
Since all of your equations are ... == 0, the problem would seem to be reducible to determining whether the polynomials on the LHSs are equivalent. For that, I think you can use CoefficientRules. I'm not super familiar with CoefficientRules, so there might be gotchas there as well.
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| Aug 22 at 4:36 | comment | added | internet | @lericr I tried ChatGPT, and it did the same thing. I'm worried about it too. | |
| Aug 22 at 4:34 | comment | added | lericr |
I assume that if you apply Simplify to all of the equations you'll end up with each of them being in a canonical form. From there you could do direct comparisons. I'm not entirely sure if this is robust for all the cases you might need.
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| Aug 22 at 4:18 | history | asked | internet | CC BY-SA 4.0 |