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May 18, 2013 at 19:58 vote accept Jon
May 18, 2013 at 19:58 comment added Jon Amazing... thank you!
May 18, 2013 at 18:20 comment added J. M.'s missing motivation Well, he can just copy the code and turn it loose on his equations... ;)
May 18, 2013 at 18:18 comment added BoLe @J.M. Yes, that's a truly great post and discussion. Should a beginner be pointed to a post like that however, it could scare him s******* easily, no?
May 18, 2013 at 18:11 comment added J. M.'s missing motivation ...and FindAllCrossings2D[] is effectively a mechanical implementation of your approach.
May 18, 2013 at 18:10 history answered BoLe CC BY-SA 3.0