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Akku14
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sol = Solve[
     4*Sin[a/2]*Cos[a/2]^3*tr + Sin[a/2] == 1 && 0 <= a <= Pi, {a, tr}, 
      Reals]

(*   {{a -> \[Pi]}, {tr -> 
       ConditionalExpression[1/4 Csc[a/2] Sec[a/2]^3 (1 - Sin[a/2]), 
        0 < a < \[Pi]]}}   *)

Plot[Evaluate[tr /. sol], {a, 0, Pi}, PlotRange -> {0, 20}, 
     GridLines -> Automatic]

{min = Minimize[tr /. sol[[2]], a], min // N}

(*   {{-(1/4) Csc[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]] Sec[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]^3 (-1 + 
 Sin[2 ArcTan[
    Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]), {a -> 
4 ArcTan[
  Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 
   3]]}}, {0.287482, {a -> 1.75015}}}   *)

Two solutions: 1. for a==Pi, any tr you like 2. For 0 < a < Pi, tr depending on a as shown in the graph.

sol = Solve[
     4*Sin[a/2]*Cos[a/2]^3*tr + Sin[a/2] == 1 && 0 <= a <= Pi, {a, tr}, 
      Reals]

(*   {{a -> \[Pi]}, {tr -> 
       ConditionalExpression[1/4 Csc[a/2] Sec[a/2]^3 (1 - Sin[a/2]), 
        0 < a < \[Pi]]}}   *)

Plot[Evaluate[tr /. sol], {a, 0, Pi}, PlotRange -> {0, 20}, 
     GridLines -> Automatic]

{min = Minimize[tr /. sol[[2]], a], min // N}

(*   {{-(1/4) Csc[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]] Sec[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]^3 (-1 + 
 Sin[2 ArcTan[
    Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]), {a -> 
4 ArcTan[
  Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 
   3]]}}, {0.287482, {a -> 1.75015}}}   *)

Two solutions: 1. for a==Pi, any tr you like 2. For 0 < a < Pi, tr as shown in the graph.

sol = Solve[
     4*Sin[a/2]*Cos[a/2]^3*tr + Sin[a/2] == 1 && 0 <= a <= Pi, {a, tr}, 
      Reals]

(*   {{a -> \[Pi]}, {tr -> 
       ConditionalExpression[1/4 Csc[a/2] Sec[a/2]^3 (1 - Sin[a/2]), 
        0 < a < \[Pi]]}}   *)

Plot[Evaluate[tr /. sol], {a, 0, Pi}, PlotRange -> {0, 20}, 
     GridLines -> Automatic]

{min = Minimize[tr /. sol[[2]], a], min // N}

(*   {{-(1/4) Csc[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]] Sec[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]^3 (-1 + 
 Sin[2 ArcTan[
    Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]), {a -> 
4 ArcTan[
  Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 
   3]]}}, {0.287482, {a -> 1.75015}}}   *)

Two solutions: 1. for a==Pi, any tr you like 2. For 0 < a < Pi, tr depending on a as shown in the graph.

added 415 characters in body
Source Link
Akku14
  • 17.4k
  • 15
  • 32
sol = Solve[
     4*Sin[a/2]*Cos[a/2]^3*tr + Sin[a/2] == 1 && 0 <= a <= Pi, {a, tr}, 
      Reals]

(*   {{a -> \[Pi]}, {tr -> 
       ConditionalExpression[1/4 Csc[a/2] Sec[a/2]^3 (1 - Sin[a/2]), 
        0 < a < \[Pi]]}}   *)

Plot[Evaluate[tr /. sol], {a, 0, Pi}, PlotRange -> {0, 20}, 
     GridLines -> Automatic] 

{min = Minimize[tr /. sol[[2]], a], min // N}

(*   {{-(1/4) Csc[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]] Sec[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]^3 (-1 + 
 Sin[2 ArcTan[
    Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]), {a -> 
4 ArcTan[
  Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 
   3]]}}, {0.287482, {a -> 1.75015}}}   *)

Two solutions: 1. for a==Pi, any tr you like 2. For 0 < a < Pi, tr as shown in the graph.

sol = Solve[
     4*Sin[a/2]*Cos[a/2]^3*tr + Sin[a/2] == 1 && 0 <= a <= Pi, {a, tr}, 
      Reals]

(*   {{a -> \[Pi]}, {tr -> 
       ConditionalExpression[1/4 Csc[a/2] Sec[a/2]^3 (1 - Sin[a/2]), 
        0 < a < \[Pi]]}}   *)

Plot[Evaluate[tr /. sol], {a, 0, Pi}, PlotRange -> {0, 20}, 
     GridLines -> Automatic]
sol = Solve[
     4*Sin[a/2]*Cos[a/2]^3*tr + Sin[a/2] == 1 && 0 <= a <= Pi, {a, tr}, 
      Reals]

(*   {{a -> \[Pi]}, {tr -> 
       ConditionalExpression[1/4 Csc[a/2] Sec[a/2]^3 (1 - Sin[a/2]), 
        0 < a < \[Pi]]}}   *)

Plot[Evaluate[tr /. sol], {a, 0, Pi}, PlotRange -> {0, 20}, 
     GridLines -> Automatic] 

{min = Minimize[tr /. sol[[2]], a], min // N}

(*   {{-(1/4) Csc[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]] Sec[
2 ArcTan[Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]^3 (-1 + 
 Sin[2 ArcTan[
    Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 3]]]), {a -> 
4 ArcTan[
  Root[1 + 2 #1 - 10 #1^2 + 2 #1^3 + #1^4 &, 
   3]]}}, {0.287482, {a -> 1.75015}}}   *)

Two solutions: 1. for a==Pi, any tr you like 2. For 0 < a < Pi, tr as shown in the graph.

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Source Link
Akku14
  • 17.4k
  • 15
  • 32

sol = Solve[
     4*Sin[a/2]*Cos[a/2]^3*tr + Sin[a/2] == 1 && 0 <= a <= Pi, {a, tr}, 
      Reals]

(*   {{a -> \[Pi]}, {tr -> 
       ConditionalExpression[1/4 Csc[a/2] Sec[a/2]^3 (1 - Sin[a/2]), 
        0 < a < \[Pi]]}}   *)

Plot[Evaluate[tr /. sol], {a, 0, Pi}, PlotRange -> {0, 20}, 
     GridLines -> Automatic]